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specific energy vs energy density

All those numbers can be complicated to explain to people. That rule of thumb assumes that the cruise L/D is 20:1. I suggest you edit the question @ParadigmPilot, just say "equivalent range and performance", Comments are not for extended discussion; this conversation has been. assembly is Pipistrel, Battery Management System (BMS) is also designed and That was me, above, Meredith Angwin. It's about 5 times less then similar pistone engine aircrafts. Do you realize just how empty a threat it would be if you told a country with a lot of nuclear power stations – “you better behave or we will not sell you any replacement fuel when you really need it – in 18-60 months.”. I'm not even talking about electric analogs of the Piper Seneca, let alone airliners. If it's true, then it somewhat contradicts the approximate power density figure of 16.7 MJ/kg given in the 1st answer. However, if I enter the numbers before your unit conversion, I get about twice your range: 200 Wh/kg, k=2/3 and L/D=20 comes out to 489 km. Keep in mind an electric motor is much smaller and lighter than an aircraft engine, and power can be distributed around the aircraft, e.g. Although batteries are often touted as the answer to most energy related problems, it's important to use the right tool to solve each problem. This is not to say that batteries are a bad way to power things. I did consider the efficiency gain from weight loss as fuel is burned, i.e. This adds mass but also adds range in day-flight, which then raises the question whether this is a day-only or night aircraft. Power density is a measure of power output per unit volume. This is probably not the way one would like to make the argument, but people are pretty clear about the distinction between a chemical explosion and an atomic explosion. Energy required = Force x Distance = Drag x Range = [Weight / (L/D)] x Range = Energy stored in the batteries, $E_{req}= F \cdot x = D \cdot R = \frac {W\cdot D}{L}\cdot R = E_{bat}$, $R \approx \frac{ E_{bat}}{W}\cdot \frac{L}{D}$, Weight = Payload + Electric power system weight + structural weight. site design / logo © 2020 Stack Exchange Inc; user contributions licensed under cc by-sa. As mentioned above a density of approx 15 MJ/kg would allow for this. In fact, nuclear power is the only energy-producing industry which takes full responsibility for all its wastes, and costs this into the product – a key factor in sustainability. Blow the rudder. of power, but that of the quality of nuclear as a power source. That might or might not be practical, depending on how you want to use an aircraft. To summarize, electric drive is currently competitive only in slower aircraft. When to carry on with a buggy game state versus terminate the process? How can a chess game with clock take 5 hours? Energy density of hydrogen tanks and fuel cell systems compared to the energy density of batteries . But, 489km is 264 nautical miles... You're right, I rounded quite a bit. Having a high energy density does not give information on how quickly this energy can be used. @ParadigmPilot Updated with additional details. EXCELLENT. )), so it would cost \$334.50 to fill up an airplane. However, they don't give any flight endurance numbers. Another way to look at energy density is on a volume basis. Former submarine Engineer Officer. That word describes a situation where there is a lack of knowledge. One of the primary advantages that nuclear energy sources have over chemical energy competitors is energy density. Is it possible to have a fully electric airliner? Energy Density (Wh/kg) is a measure of how much energy a battery can hold. Energy Density (Wh/liter) H2Gen: Wt_Vol_Cost.XLS; Tab 'Battery'; S34 - 3 / 25 / 2009 . (20%-95% range), 6hrs with 3kW charger, 1h 40' with 10 kW charger, 1h 5' with 14 kW, 45 Do you ever wish they’d let us have smokestacks and ash ponds? Resume available here. ZX Spectrum 48k Power Supply outputting 15V. Internal combustion engines are 35% efficient and electric engines 90%, so we can calculate that an electric airplane would need 5130 * 0.35 / 0.9 = 1995 MJ of electrical power to fill up. By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy. @Harper I'm only talking about in flight solar power, not electric airplanes in general. Based on what I know about PopAtomic, they feel the same way. The small motor means a slimmer cowling, which they claim reduces air resistance by 15% and allows the prop to generate "considerably more thrust". Specifications by Battery Chemistry. It isn’t just a question that nuclear power is overwhelmingly more energy-flux-dense than prior forms Also, will it be cheaper to charge as opposed to the cost of liquid fuel? How to make non-linear movements with a Follow Path constraint? Drag increases with the square of speed, more drag means more batteries needed to supply the power, and that means more weight. Batteries would need to be somewhere around 16.7MJ/kg to give the same range and performance as liquid fuels, this is about 18.5 times the capacity of the best lithium-ion batteries. I'm going to do separate calculations for the US and UK to see how they compare: EDIT: According to the theory, power equals energy divided by time; i.e. For example - 300 NM cross country flight for the CPL training. How about an Ad showing the solid waste from a coal plant for a year vs. the storage container for a years worth of fuel rods? So, 20:1 is ambitious, but realistic. For airplanes where a more significant portion of the weight is fuel, i.e.

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